posted by Anonymous
A finite geometric sequence has t1= 0.1024 and t2= 0.256 how many terms does this sequence have if its middle temr has the value 156.25?
how would go about and do this question?
If t1 = 0.1024 and t2 = 0.256, then the common ratio is t2/t1 = 2.5
The value at term n is given by .1024 * 2.5 n-1, therefore solve
156.25 = .1024 * 2.5 n-1 to find the middle term.
guess and check on finding the middle term (it's 9) to get 18 terms
mathematically I thought you were supposed to log both sides
log156.25 = log(.1024*2.5)^n-1
log156.25 = n-1log(.256)<--power of log rule
I did something wrong though... because my answer isn't right