What happens to the graph of the line y = 3x -2 when the equation is changed to y = 3x +6?
What happens to the graph of the line y = 2x - 5 when the equation is changed to y = 5x + 6?
On the first question:
What happens to the graph of the line y = 3x -2 when the equation is changed to y = 3x +6?
The new line is parallel to the old line, shifted upward.
On the second queation.What happens to the graph of the line y = 2x - 5 when the equation is changed to y = 5x + 6
The line is moved upward, and slopes much more up.
Thanks!!How do you find the x and y interepts of each linear equation as ordered pairs:
a.y=3x-6
b.6y=x+2
This was posted in 2006 and no one still hasn't answered her. Legend says Margie is still waiting for help.
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To find the x and y intercepts of a linear equation, we can substitute x=0 to find the y-intercept, and substitute y=0 to find the x-intercept.
For equation (a) y=3x-6:
To find the y-intercept, substitute x=0 into the equation:
y = 3(0) - 6
y = -6
So the y-intercept is (0, -6).
To find the x-intercept, substitute y=0 into the equation:
0 = 3x -6
3x = 6
x = 2
So the x-intercept is (2, 0).
For equation (b) 6y = x + 2:
To find the y-intercept, substitute x=0 into the equation:
6y = 0 + 2
6y = 2
y = 1/3
So the y-intercept is (0, 1/3).
To find the x-intercept, substitute y=0 into the equation:
6(0) = x + 2
0 = x + 2
x = -2
So the x-intercept is (-2, 0).
I hope this helps! Let me know if you have any further questions.
To find the x and y intercepts of a linear equation, you can use the following steps:
a) To find the x-intercept (where the line crosses the x-axis), set y = 0 and solve for x:
- Set y = 0 in the equation y = 3x - 6:
0 = 3x - 6
- Add 6 to both sides to isolate the term with x:
6 = 3x
- Divide both sides by 3 to solve for x:
x = 2
Therefore, the x-intercept is (2, 0).
- To find the y-intercept (where the line crosses the y-axis), set x = 0 and solve for y:
x = 0 in the equation y = 3x - 6:
y = 3(0) - 6
y = -6
Therefore, the y-intercept is (0, -6).
b) To find the x-intercept (where the line crosses the x-axis), set y = 0 and solve for x:
- Set y = 0 in the equation 6y = x + 2:
6(0) = x + 2
0 = x + 2
- Subtract 2 from both sides to isolate the term with x:
-2 = x
Therefore, the x-intercept is (-2, 0).
- To find the y-intercept (where the line crosses the y-axis), set x = 0 and solve for y:
x = 0 in the equation 6y = x + 2:
6y = 0 + 2
6y = 2
y = 2/6
y = 1/3
Therefore, the y-intercept is (0, 1/3).
So, for the equations:
a) y = 3x - 6, the x-intercept is (2, 0) and the y-intercept is (0, -6).
b) 6y = x + 2, the x-intercept is (-2, 0) and the y-intercept is (0, 1/3).