chem

posted by .

What volume of a 0.2 N NaoH solution do you expect to use in order to titrate 25ml (sample out of 250ml) of a 0.200 N oxalic acid solution?
heeeelp!


Equation is
H2C2O4 + 2NaOH==> 2H2O + Na2C2O4

I assume that is 25.00 mL H2C2O4.
milliequivalents(meq) NaOH = meq H2C2O4
25 mL x 0.2 = ??mL x 0.200
Do you suppose 25.00 mL.

Most schools don't teach normality now, but notice how easy it is to use normality. There are no mols and then convert mols H2C2O4 to mols NaOH, then mols/L = M for NaOH. It is all done for us by using normality. Neat!!


wow...thanks DrBob, I'll try it!


The problem will come when the question does NOT provide normality but provides molarity. Then you must convert M to N yourself OR work it the long way using mols. But note that whereas mL x N = mL x N (ALWAYS, ALWAYS, ALWAYS), mL x M /=/ (is not equal) mL x M EXCEPT when you want to work a dilution problem. For a stoichiometry problem, however, mL x M = mL x M is true ONLY when the reacting ratios are 1:1 (or 2:2 or 3:3 etc).


Thanks...I didn't know that

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    Calculate the molarity of an aqueous NaOH soultion if 32.00ml of it is required to titrate. 0.6789 g of oxalic acid to phenolphthalein end point. The balanced chemical equation is H2C2O4 + 2NaOH-> Na2C2O4 + 2H2O
  2. college Chemistry

    What is the mole of oxalic acid? Equation:H2C2O4 + 2NaOH---> Na2C2O4 + 2H2O *Moles of oxalic acid dihydrate is 0.032 mole. * Molarity of oxalic acid solution is 0.128 M oxalic acid solution. * Initial volume of Oxalic acid is 19.8
  3. Chemistry

    What is the mole of oxalic acid? Equation:H2C2O4 + 2NaOH---> Na2C2O4 + 2H2O *Moles of oxalic acid dihydrate is 0.032 mole. * Molarity of oxalic acid solution is 0.128 M oxalic acid solution. * Initial volume of Oxalic acid is 19.8
  4. Higher Chem

    A 0.5537-g sample containing oxalic acid required 21.62 mL of 0.09377 M NaOH for titration. If the reaction is H2C2O4 + 2NaOH  Na2C2O4 + 2H2O, calculate the % H2C2O4 in the sample.
  5. Chemisty

    A 2.5 L volume of sodium hydroxide solution was prepared. The titrant was standarized against primary standard oxalic acid dihydrate, H2C2O4*H2O(molar mass is 126.06) if a 0.4774g sample of the prmiary standard consumed 31.94mL of …
  6. Chemistry

    25.00 mL of a solution of oxalic acid are titrated with 0.2586 m NaOH (aq). The stoichiometric eend point is reached when 43.42 mL of the solution of base is added. What is the molarity of the oxalic acid solution?
  7. Chem 100L

    Calculate the molarity of an aqueous NaOH solution if 32.00ml of it is required to titrate .6789g of oxalic acid to a phenophthalein end-point. the balanced chemical equation is H2C2O4 + 2NaOH ---> Na2C2O4 + 2H2O
  8. chemistry

    For each of the following primary standard acids, write the titration equation and calculate the volume of 0.100 M NaOH required for the titration: (i) 300 mg benzoic acid (C6H5COOH) (ii) 200 mg oxalic acid dihydrate (C2O4H2.2H2O) …
  9. Chemistry

    24) It was found that a 20.00 mL portion of a solution of oxalic acid, H2C2O4, requires 6.69 mL of 0.200 M K2Cr2O7 for complete reaction in an acidic solution. In the reaction, the oxidation product is CO2 and the reduction product …
  10. Chemistry

    1. A sample of oxalic acid (H2C2O4, with two acidic protons), of volume 46.56 mL was titrated to the stoichiometric point with 17.06 mL of 0.297 M NaOH(aq). What is the molarity of the oxalic acid?

More Similar Questions