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If cosec A – sin A=a3 , sec A – cos A =b3 , prove that
a2 b2 (a2 + b2)=1


Since the first two equations involves two constants a3 and b3, one cannot prove the third equation with totally different constants a2 and b2. Is a3 supposed to be a-cubed and a2 supposed to be a-squared?


If a2 is supposed to be a-squared and a3 is supposed to be a-cubed, please use ^2 to denote second power and ^3 to denote third power, etc., and use that notation in future questions that you may sumbit.

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