dividing a polynomial by a polynomial
posted by Angel007 .
(6v^2  4 + 9v +v^3)/ (v  4)i am just a little lost can someone explain this to me. thanks.
Arrange the polonomial in descending order...
v^36v^2 +9v 4
Then divide.
v4 !v^36v^2 +9v 4
The first term is v^2, so v^2*(v4) is
v^34v^2
subtracting that from the polonomial gives
v4 ! 2v^2+9v4
so dividing one gets 2v, then multiplying by v4 gives
2v(v4)=2v^2+8v, and subtracting that frm 2v^2+9v4 gives
v4 ! v4, and dividing gives 1.
so the answer is v^2 2v +1
check my thinking.
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