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Angle calculations and Bearings
Questions (1)
tan 39°=40/AP, So AP =40/tan. in triangle AQP, angle Q= 60/sin 91°=AP/SinQ. Then bearing of Qfrom P = 30° 180°-(91 angle Q).
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asked by
Vin Mwale
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Parent Categories (1)
Trigonometric Equations and Identities
