Derive the equation of the line in slope-intercept form. 0,-2 and 3,0
First, let's find the slope of the line using the given points (0, -2) and (3, 0).
Slope (m) = (y2 - y1) / (x2 - x1)
m = (0 - (-2)) / (3 - 0)
m = 2 / 3
Now that we have the slope, we can use one of the points to find the y-intercept (b). Let's use the point (0, -2).
y = mx + b
-2 = (2/3)(0) + b
b = -2
Now, we can write the equation of the line in slope-intercept form:
y = (2/3)x - 2