(1,-1) (0,-4)
Using the graph, derive the equation of the line in slope-intercept form.
(1 point)
0 3x - y = 4
0 y = -3x - 4
0 y = 3x - 4
0 y = 3x + 4
HERE ARE ALL ANSWER!
1: y = 3x - 4
2: y = -5x + 1
3: D (aka the one that shows (0, 2) and (1, -1))
4: No, it's not the correct graph because this graph used (0, 3) as the Y-intercept
5: A (aka the one that shows (0, -1) and (3, 1))
To find the equation of the line in slope-intercept form, we need to determine the slope and the y-intercept.
We are given two points on the line, (1, -1) and (0, -4).
The slope of the line can be found using the formula m = (y2 - y1) / (x2 - x1). Let's choose (1, -1) as (x1, y1) and (0, -4) as (x2, y2).
m = (-4 - (-1)) / (0 - 1)
m = (-4 + 1) / (-1)
m = -3 / (-1)
m = 3
So, the slope of the line is 3.
Now, let's find the y-intercept. We can use the slope-intercept form of a line, y = mx + b, where m is the slope and b is the y-intercept.
Using the point (1, -1), we can substitute the values into the equation and solve for b:
-1 = 3(1) + b
-1 = 3 + b
b = -1 - 3
b = -4
So, the y-intercept is -4.
Therefore, the equation of the line in slope-intercept form is y = 3x - 4.
To find the equation of the line in slope-intercept form, we need to determine the slope and the y-intercept using the given points (0, 1) and (1, -4).
The slope of the line can be found using the formula m = (y2 - y1) / (x2 - x1), where (x1, y1) and (x2, y2) are the coordinates of the points.
m = (-4 - 1) / (1 - 0)
m = -5 / 1
m = -5
So, the slope of the line is -5.
Now, let's find the y-intercept. We can use the slope-intercept form of a line, y = mx + b, where m is the slope and b is the y-intercept.
Using the point (0, 1), we can substitute the values into the equation and solve for b:
1 = -5(0) + b
1 = b
So, the y-intercept is 1.
Therefore, the equation of the line in slope-intercept form is y = -5x + 1.
(0,1) (1,-4)
Write the equation of the line in slope-intercept form.
(1 point)
0 y = -5x +1
0 y =-5x-1
0 -5x - y= -1
• y = 5x + 1
Graph the linear equation y =-3x + 2.
(1,5) (0,3)
(0,-2) (1,5)
(-2,2) (0,1)
(0,2) (1,-1)
To graph the linear equation y = -3x + 2, we can use the given points (1,5) and (0,3), which are points on the line.
First, plot the given points (1,5) and (0,3) on the coordinate plane.
The point (1,5) means that when x = 1, y = 5. So, plot the point (1,5) on the graph.
The point (0,3) means that when x = 0, y = 3. So, plot the point (0,3) on the graph.
After plotting the two points, you can connect them to create the graph of the line.
The final graph of the line y = -3x + 2 should look like a straight line that passes through the points (1,5) and (0,3).
(0,3) (3,2)
Is this the correct graph of y=-‡a +1? (1 point)
No, it is not the correct
O graph because this graph has a positive slope.
Yes, it is the correct graph
• because this graph has a Y-intercept of (0, 4).
No, it is not the correct graph because this graph used (0, 3) as the y-intercept.
Yes, it is the correct graph
• because this graph has a y-intercept of (0, 3).
No, it is not the correct graph because this graph has a y-intercept of (0, 3), whereas y = -‡a +1 has a y-intercept of (0, 1).
(0,3) (3,2)
Is this the correct graph of y=-1/3x +4? (1 point)
No, it is not the correct
O graph because this graph has a positive slope.
Yes, it is the correct graph
• because this graph has a Y-intercept of (0, 4).
No, it is not the correct graph because this graph used (0, 3) as the y-intercept.
Yes, it is the correct graph
• because this graph has a y-intercept of (0, 3).