use the graph to derive the equation of the line in slope-intercept form. (1 point) 1,3 0,-2
First, let's find the slope of the line using the given points (1,3) and (0,-2):
Slope = (y₂ - y₁)/(x₂ - x₁)
= (-2 - 3)/(0 - 1)
= -5/-1
= 5
Next, we can use one of the given points to find the y-intercept of the line:
Using point (1,3):
y = mx + b
3 = 5(1) + b
b = -2
Now we can write the equation of the line in slope-intercept form:
y = 5x - 2
try again
My apologies for the mistake. Let's try again using the given points (1,3) and (0,-2).
First, let's find the slope of the line using the given points:
Slope = (y₂ - y₁)/(x₂ - x₁)
= (-2 - 3)/(0 - 1)
= -5/-1
= 5
Next, we can use one of the given points to find the y-intercept of the line:
Using point (1,3):
y = mx + b
3 = 5(1) + b
b = 3 - 5
b = -2
Now we can write the equation of the line in slope-intercept form:
y = 5x - 2