Derive the equation of the line in slope-intercept form. (1 point) points are at (0,2) & (1,-1)
To find the equation of the line passing through the points (0,2) and (1,-1), we first need to find the slope of the line using the formula:
m = (y2 - y1) / (x2 - x1)
Substitute the coordinates of the points into the formula:
m = (-1 - 2) / (1 - 0)
m = -3 / 1
m = -3
Now that we have the slope, we can use the point-slope form of the equation of a line to find the equation in slope-intercept form:
y - y1 = m(x - x1)
Using the point (0,2):
y - 2 = -3(x - 0)
y - 2 = -3x
y = -3x + 2
Therefore, the equation of the line passing through the points (0,2) and (1,-1) in slope-intercept form is y = -3x + 2.