what are the values of the coefficients a, b, and c when solving this equation for x when using the quadratic formula? 6 x 10^-3 = x^2 / (0.04-x)?
The equation 6x 10^-3 = x^2 / (0.04-x) can be rewritten as x^2 / (0.04-x) - 6x 10^-3 = 0.
To solve this equation using the quadratic formula, we need to identify the values of the coefficients a, b, and c.
The equation is in the form ax^2 + bx + c = 0, so we can identify the following coefficients:
a = 1 (the coefficient of x^2 is 1)
b = -6x 10^-3 (the coefficient of x is -6x 10^-3)
c = 0 (the constant term is 0)
Therefore, the values of the coefficients a, b, and c when solving this equation using the quadratic formula are:
a = 1
b = -6x 10^-3
c = 0