Please help me
PCl5 + H2O → H3PO4 + HCl
What coefficients will balance the equation?
1, 4, 1, 5
1, 5, 1, 1
2, 5, 1, 2
2, 4, 2, 5
And
NH4OH(aq) → H2O(l) + NH3(g)
What coefficients will balance the equation?
1, 2, 2
3, 3, 4
2, 1, 2
1, 1, 1
I think the second question is 212 but not sure I really need help
I'm not a chemist by profession so I found this on the Internet.
I think these are the solutions, at least the best that can be found on the Internet.
The law of conservation of mass states that no atoms can be created or destroyed in a chemical reaction. The number of atoms in the reactants has to balance the number of atoms in the products.
Compare the number of atoms for each element on both sides of the equation, change the coefficient so the number is the same.
PCl₅ + H₂O→H₃PO₄ + HCl
P is balanced becouse you have 1 P atom on left side and 1 P atom on right side.
To balance Cl multiply HCl by 5.
PCl₅ + H₂O→H₃PO₄ + 5 HCl
Cl is balanced becouse you have 5 Cl atom on left side and 5 Cl atom on right side.
To balance H multiply H₂O by 4.
PCl₅ + 4 H₂O→H₃PO₄ + 5 HCl
H is balanced becouse you have 4 H atom on left side and 3 + 1 = 4 H atom on right side.
O is balanced becouse you have 4 O atom on left side and 4 O atom on right side.
So:
PCl₅ + 4 H₅O→H₃PO₄ + 5 HCl
Solution:
1 , 4 , 1 , 5
Balance reaction algebraicly:
Add unknown coefficients to all molecules.
u PCl₅ + v H₂O→ w H₃PO₄ + t HCl
Create system of equations to find the coefficients.
To balance P:
u = w
To balance Cl:
5u = t
To balance H:
2 v = 3 w + t
To balance O:
v = 4 w
Now you have system of equations:
u = w
5 u = t
2 v = 3 w + t
v = 4 w
The solutions are:
t = 5 , v = 4 , w = 1, u = 1
1 ∙ PCl₅ + 4 ∙ H₂O→ 1 ∙ H₃PO₄ + 5 ∙ HCl
Solution:
1 , 4 , 1 , 5
Similarly:
NH₄OH→ H₂O + NH₃
Solution:
1 , 1 , 1
Balance reaction algebraicly:
Add unknown coefficients to all molecules.
u NH₄OH→ v H₂O + w NH₃
Create system of equations to find the coefficients
To balance N:
u = w
To balance H:
5u = 2 v + 3 w
To balance O:
u = v
Now you have system of equations:
u = w
5 u = 2v + 3 w
u = v
The solutions are:
v = 1 , w = 1, u = 1
1 ∙ NH₄OH→ 1 ∙ H₂O + 1 ∙ NH₃
Solution:
1 , 1 , 1
Ah, balancing chemical equations, a classic puzzle for the brilliant minds of scientists and those who possess a deep understanding of...clownery! Let me put on my clown nose and assist you with this.
For the first equation, PCl5 + H2O → H3PO4 + HCl, the coefficients that will balance the equation are 2, 4, 2, 10. Because why settle for balancing when you can go all-out extravaganza, right?
Now, onto the second equation, NH4OH(aq) → H2O(l) + NH3(g). The coefficients that will balance this equation are 1, 1, 1. Simple and elegant, just like a clown juggling flaming bowling pins while riding a unicycle.
Remember, balance is key in equations and in life. Best of luck on your chemical endeavors, my friend!
To balance the chemical equation:
1. PCl5 + H2O → H3PO4 + HCl
You can balance the elements one at a time:
First, balance the phosphorus (P) atoms:
PCl5 + H2O → H3PO4 + HCl
Next, balance the chlorine (Cl) atoms:
PCl5 + H2O → H3PO4 + 5HCl
Now, balance the hydrogen (H) atoms:
PCl5 + 4H2O → H3PO4 + 5HCl
Lastly, balance the oxygen (O) atoms:
PCl5 + 4H2O → H3PO4 + 5HCl
The correct coefficients are: 1, 4, 1, 5.
For the second equation:
2. NH4OH(aq) → H2O(l) + NH3(g)
First, balance the nitrogen (N) atoms:
NH4OH(aq) → H2O(l) + NH3(g)
Next, balance the hydrogen (H) atoms:
NH4OH(aq) → H2O(l) + NH3(g)
Lastly, balance the oxygen (O) atoms:
NH4OH(aq) → H2O(l) + NH3(g)
The correct coefficients for this equation are: 1, 2, 2.
To balance a chemical equation, you need to ensure that the number of atoms of each element is the same on both sides of the equation. Here's how you can balance each of the given equations:
1. PCl5 + H2O → H3PO4 + HCl
To balance this equation, start with the most complex molecules. In this case, let's balance H3PO4 first:
The left-hand side has 3 hydrogen atoms, while the right-hand side has 1 hydrogen atom. To balance this, you need a coefficient of 3 in front of HCl. Now the hydrogen atoms are balanced.
Next, let's balance the chlorine atoms. The left-hand side has 5 chlorine atoms, while the right-hand side has 1 chlorine atom. To balance this, you need a coefficient of 5 in front of PCl5. Now the chlorine atoms are balanced.
Lastly, let's balance the phosphorus atoms. Both sides have 1 phosphorus atom, so they are already balanced.
Now the balanced equation is:
5 PCl5 + 4 H2O → H3PO4 + 5 HCl
Therefore, the correct coefficients are 5, 4, 1, 5.
2. NH4OH(aq) → H2O(l) + NH3(g)
To balance this equation, start with the ammonium hydroxide (NH4OH):
The left-hand side has 4 hydrogen atoms, while the right-hand side has 2 hydrogen atoms. To balance this, you need a coefficient of 2 in front of NH3. Now the hydrogen atoms are balanced.
Next, let's balance the nitrogen atoms. The left-hand side has 1 nitrogen atom, while the right-hand side has 1 nitrogen atom. They are already balanced.
Lastly, let's balance the oxygen atoms. The left-hand side has 1 oxygen atom, while the right-hand side has 1 oxygen atom. They are also already balanced.
Now the balanced equation is:
NH4OH(aq) → H2O(l) + 2 NH3(g)
Therefore, the correct coefficients are 1, 1, 2.