You need 5.8 oz
of a steroid ointment. If there are 16 oz
in 1 lb
, how many grams of ointment does the pharmacist need to prepare?
To convert ounces to pounds, divide the number of ounces by 16:
5.8 oz / 16 oz/lb = 0.3625 lb
Now, since there are 1 lb in 453.592 grams, multiply the number of pounds by this conversion factor:
0.3625 lb * 453.592 g/lb = 164.2055 g
Therefore, the pharmacist needs to prepare approximately 164.21 grams of ointment.
To convert ounces to pounds, divide the number of ounces by 16.
Therefore, 5.8 oz ÷ 16 oz/lb = 0.3625 lbs.
To convert pounds to grams, multiply the number of pounds by 453.592 grams/lb.
Therefore, 0.3625 lbs × 453.592 grams/lb = 164.205 grams.
So, the pharmacist needs to prepare 164.205 grams of ointment.
To find the number of grams of ointment needed, we need to convert the given 5.8 oz to grams. Here's how you can do that:
1. First, convert ounces to pounds. Since there are 16 oz in 1 lb, we divide 5.8 oz by 16 oz/lb to get the equivalent in pounds:
5.8 oz ÷ 16 oz/lb = 0.3625 lb
2. To convert pounds to grams, we need to know the conversion factor between pounds and grams. There are 453.592 grams in 1 pound.
Multiply 0.3625 lb by 453.592 g/lb:
0.3625 lb × 453.592 g/lb ≈ 164.6547 g
So, the pharmacist needs to prepare approximately 164.65 grams of ointment.