You need 3.1 oz
of a steroid ointment. If there are 16 oz
in 1 lb
, how many grams of ointment does the pharmacist need to prepare?
To convert from pounds to grams, we need to know the conversion factor. 1 pound is equal to 453.592 grams.
First, we need to convert 3.1 oz to pounds. Since there are 16 oz in 1 lb, we have:
3.1 oz / 16 oz/lb = 0.19375 lb
Next, we can convert 0.19375 lb to grams:
0.19375 lb * 453.592 g/lb = 87.884525 g
Therefore, the pharmacist needs to prepare 87.884525 grams of ointment.
To answer this question, we need to convert the given measurements.
1 pound (lb) is equal to 16 ounces (oz). So, if we have 3.1 ounces, we can convert it to pounds by dividing it by 16:
3.1 oz / 16 oz per lb = 0.19375 lb
Now, we need to convert pounds to grams.
There are 453.592 grams (g) in 1 pound (lb). So, to find the grams in 0.19375 lb, we can multiply it by the conversion factor:
0.19375 lb * 453.592 g per lb = 87.959875 g
Rounding to an appropriate decimal place, the pharmacist needs to prepare approximately 87.96 grams of ointment.
To answer this question, we need to convert the given units to the desired unit.
First, let's convert ounces to pounds. We know that there are 16 ounces in 1 pound. Therefore, to convert 3.1 ounces to pounds, we need to divide it by 16:
3.1 oz ÷ 16 = 0.19375 lb (rounded to five decimal places)
Next, we need to convert pounds to grams. We'll use the conversion factor that 1 pound is equal to 453.592 grams. To find the weight in grams, we multiply the weight in pounds by the conversion factor:
0.19375 lb × 453.592 g/lb = 87.8719 g (rounded to four decimal places)
Therefore, the pharmacist would need to prepare approximately 87.872 grams of ointment.