You need 3.6 oz
of a steroid ointment. If there are 16 oz
in 1 lb
, how many grams of ointment does the pharmacist need to prepare?
To convert ounces to pounds, we divide the number of ounces by 16: 3.6 oz ÷ 16 oz/lb = 0.225 lbs.
1 pound is approximately equal to 453.592 grams, so to convert pounds to grams, we multiply the number of pounds by 453.592: 0.225 lbs * 453.592 g/lb = 102.308 grams.
Therefore, the pharmacist needs to prepare 102.308 grams of ointment.
To convert ounces to pounds, divide the number of ounces by 16, since there are 16 ounces in 1 pound.
3.6 ounces / 16 ounces per pound = 0.225 pounds
To convert pounds to grams, multiply the number of pounds by 453.59237, since there are 453.59237 grams in 1 pound.
0.225 pounds * 453.59237 grams per pound = 102.16890275 grams
Therefore, the pharmacist needs to prepare 102.17 grams of ointment.
To find the number of grams of ointment the pharmacist needs to prepare, we need to convert ounces to grams.
First, let's convert 3.6 ounces to pounds. Since there are 16 ounces in 1 pound, we divide 3.6 ounces by 16 to get the equivalent in pounds:
3.6 oz ÷ 16 oz/lb = 0.225 lb
Next, we need to convert pounds to grams. There are approximately 453.59237 grams in 1 pound, so we multiply the pounds by this conversion factor to get the equivalent in grams:
0.225 lb × 453.59237 g/lb = 102.31865625 g
Therefore, the pharmacist needs to prepare approximately 102.32 grams of ointment.