A farmer conducted an inventory on his two square kilometers of rainforest; the results are in the table. He plans on randomly selecting a seedling to experiment on when he goes back to the forest. What is the probability that he will randomly pick a type B plant? Write your answer in the simplest form of a fraction.
1. 1/3
2. 0.88
3. 30%
4. 8%
5. 0.003
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its 1/3!!!!!
The department reported that out of 2,500 tested bulbs, 2,200 burnt out after more than 1,500 hours of use. This means that the percentage or proportion of bulbs that lasted more than 1,500 hours is:
2,200/2,500 = 0.88 or 88%
Therefore, the likelihood or probability that Lucy's light bulb from Company X will burn for more than 1,500 hours is 88% or 0.88 as a decimal.
Sure, here are the answers expressed as fractions:
1. 1/3
2. 22/25
3. 3/10
4. 2/25
5. 3/1000
To find the probability of selecting a type B plant, we need to divide the number of type B plants by the total number of plants:
Probability of selecting a type B plant = Number of type B plants / Total number of plants
There are a total of 300+1000+720+80+900+1200 = 3200 plants in the forest.
There are 720 plants of type B.
Therefore, the probability of selecting a type B plant is:
Probability of selecting a type B plant = 720 / 3200
Simplifying the fraction by dividing the numerator and denominator by 80 (their greatest common factor), we get:
Probability of selecting a type B plant = 9 / 40
Therefore, the probability of randomly selecting a type B plant from the rainforest is 9/40.
Company X tested its light bulbs to see how long they would last. On a production line, 2,500 bulbs were taken and tested. The department in charge reported that out of 2,500 bulbs, there were 2,200 bulbs that burnt out after more than 1,500 hours of use. Lucy purchased a light bulb from Company X. What is the likelihood that it will burn for more than 1,500 hours? Write your answer in decimal form.
The letter tiles C, A, R, E, and S are placed in a box. Without looking, Jorelle picks a letter tile from the box and records the result before placing it back. He repeats the procedure 100 times and observes Based on the observed frequency, what is the probability that Jorelle will pick a letter R? The answer should be in percent form
If the experiment is done by picking a letter tile randomly from the box and placing it back, then each time there is an equal chance of picking any of the five letters. Therefore, the probability of picking the letter R on any one trial is 1/5 or 0.2.
Since Jorelle repeated the procedure 100 times, the expected number of times that he would pick the letter R is:
Expected number of times = probability of success x number of trials
Expected number of times = (1/5) x 100
Expected number of times = 20
Therefore, if the experiment is repeated many times under the same conditions, we would expect Jorelle to pick the letter R about 20 times out of 100.
However, the question asks for the probability based on the observed frequency, which we don't have. So, we can only estimate the probability based on the proportion of times that Jorelle actually picked the letter R in his 100 trials.
For example, if Jorelle picked the letter R 25 times out of 100, the observed frequency of picking letter R is 25/100 or 0.25. This is higher than the expected frequency of 0.2, but it could be due to chance variation.
The probability of picking the letter R based on the observed frequency would then be 25% (or 0.25 as a decimal), but this would be only an estimate and not necessarily the true probability.
Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results are recorded in the table. What is the largest discrepancy between the experimental and the expected probability of this experiment? The answer needs to be in percent form to the nearest whole number.
To find the expected probability of rolling each number on the cube, we divide the number of ways to roll that number by the total number of possible outcomes:
- The probability of rolling 2 is 1/6 or about 16.67%.
- The probability of rolling 4 is 1/6 or about 16.67%.
- The probability of rolling 6 is 1/6 or about 16.67%.
- The probability of rolling 8 is 1/6 or about 16.67%.
- The probability of rolling 10 is 1/6 or about 16.67%.
- The probability of rolling 12 is 1/6 or about 16.67%.
The expected probabilities are all the same because the cube is fair and the outcomes are equally likely.
To find the experimental probabilities, we can divide the number of times each number was rolled by the total number of rolls:
- The experimental probability of rolling 2 is 10/100 or 10%.
- The experimental probability of rolling 4 is 16/100 or 16%.
- The experimental probability of rolling 6 is 16/100 or 16%.
- The experimental probability of rolling 8 is 24/100 or 24%.
- The experimental probability of rolling 10 is 18/100 or 18%.
- The experimental probability of rolling 12 is 16/100 or 16%.
The largest discrepancy between the expected and experimental probabilities occurs for rolling 8. The expected probability is 16.67% but the experimental probability is 24%. The absolute difference between these probabilities is 24% - 16.67% = 7.33%.
Therefore, the largest discrepancy between the experimental and expected probability is 7% (to the nearest whole number).