a farmer conducted an inventory on his two square kilometers of rainforest; the results are in the table below. he plans on randomly selecting a seedling to experiment on when he goes back to the forest. what is the probability that he will randomly pick a type B seed?
A=100 B=140 C=80 D=60 E=40! bot help please
The probability that the light bulb will burn out for more than 1500 hours can be estimated by the proportion of bulbs in the sample that burned out after more than 1500 hours:
2200/2500 = 0.88
So the probability that the light bulb will burn out for more than 1500 hours is 0.88 or 88%.
company x tested its light bulbs to see how long they would last. on a production line, 2500 bulbs were taken and tested. the department in charge reported that out of 2500 bulbs, there were 2200 that burnt out after more than 1500 hours of use. Lucy purchased a light bulb from company x, what is the likelihood that it will burn out for more than 1500 hours
the letter tiles C, A, R, E, and S are placed in a box. without looking, jorelle picks a letter file from the box and records the results. he repeats the procedure 100 times and observes the following
C=20 A=25 R=30 E=10 S=12
based on that, what is the probability jorelle will pick the letter R? percent form
The probability of picking the letter R can be estimated by dividing the number of times R was picked by the total number of times Jorelle made a selection:
30/100 = 0.3
Multiplying by 100 to convert to a percentage, we get:
30%
Therefore, the probability that Jorelle will pick the letter R is 30%.
Need tossed a cube with faces numbered with 2.4.6.8.and 12 the results are recorded in the table. What is the largest and smallest discrepancy between the experimental and expected probability? 3 decimal places
outcomes: 2,4,6,8,10,12
frequency: 10,9,6,15,13,8
The total number of seedlings is:
100 + 140 + 80 + 60 + 40 = 420
The probability of randomly picking a type B seedling is:
140/420
Simplifying the fraction by dividing both the numerator and denominator by 20, we get:
7/21
Therefore, the probability of randomly picking a type B seedling is 7/21 or approximately 0.3333.
The expected probability of each outcome can be calculated as 1/6 since there are six equally likely outcomes on the cube. To calculate the expected frequency, we multiply the expected probability by the total number of tosses:
Expected probability = 1/6
Total tosses = 10 + 9 + 6 + 15 + 13 + 8 = 61
Expected frequency of 2 = (1/6) x 61 = 10.17
Expected frequency of 4 = (1/6) x 61 = 10.17
Expected frequency of 6 = (1/6) x 61 = 10.17
Expected frequency of 8 = (1/6) x 61 = 10.17
Expected frequency of 10 = (1/6) x 61 = 10.17
Expected frequency of 12 = (1/6) x 61 = 10.17
We can now calculate the discrepancies between the expected and experimental frequencies for each outcome:
Discrepancy of 2 = 10 - 10.17 = -0.17
Discrepancy of 4 = 9 - 10.17 = -1.17
Discrepancy of 6 = 6 - 10.17 = -4.17
Discrepancy of 8 = 15 - 10.17 = 4.83
Discrepancy of 10 = 13 - 10.17 = 2.83
Discrepancy of 12 = 8 - 10.17 = -2.17
The maximum discrepancy between the experimental and expected probability is 4.83, and the minimum discrepancy is -4.17 (ignoring the negative signs). Therefore, the largest discrepancy is 4.83 and the smallest discrepancy is 0.17 (since it has the smallest absolute value).