Use the table to answer the question.
Plant Types A B C D E
Number of Seedlings 100 140 80 60 40
A farmer conducted an inventory on his two square kilometers of rainforest; the results are in the table. He plans on randomly selecting a seedling to experiment on when he goes back to the forest. What is the probability that he will randomly pick a type B plant? Write your answer in the simplest form of a fraction.
There are a total of 420 seedlings (100+140+80+60+40) and 140 of them are type B.
So, the probability of randomly picking a type B plant is:
140/420 = 1/3
Therefore, the probability is 1/3.
Company X tested its light bulbs to see how long they would last. On a production line, 2,500 bulbs were taken and tested. The department in charge reported that out of 2,500 bulbs, there were 2,200 bulbs that burnt out after more than 1,500 hours of use. Lucy purchased a light bulb from Company X. What is the likelihood that it will burn for more than 1,500 hours? Write your answer in decimal form.
Out of 2,500 bulbs, 2,200 burnt out after more than 1,500 hours of use.
The probability that a randomly selected bulb will burn out after more than 1,500 hours of use is:
2200/2500 = 0.88
So the likelihood, or probability, that Lucy's light bulb will burn for more than 1,500 hours is 0.88, or 88%.
The letter tiles C, A, R, E, and S are placed in a box. Without looking, Jorelle picks a letter tile from the box and records the result before placing it back. He repeats the procedure 100 times and observes the following results:
Outcomes C A R E S
Frequency 20 25 30 10 15
Based on the observed frequency, what is the probability that Jorelle will pick a letter R? The answer should be in percent form.
Jorelle picked a letter tile from the box 100 times and recorded the following frequency:
Outcomes C A R E S
Frequency 20 25 30 10 15
The probability of Jorelle picking a letter R can be calculated by dividing the frequency of R by the total number of picks:
P(R) = Frequency of R / Total number of picks
P(R) = 30 / 100
P(R) = 0.3
To convert to percent form, we multiply by 100:
P(R) = 0.3 * 100
P(R) = 30%
Therefore, the probability that Jorelle will pick a letter R is 30%.
Use the table to answer the question.
Outcomes 2 4 6 8 10 12
Frequency 10 9 6 15 13 8
Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results are recorded in the table. What is the largest discrepancy between the experimental and the expected probability of this experiment? The answer needs to be in percent form to the nearest whole number.
The expected probability of rolling each number can be calculated by dividing the number of ways to roll that number by the total number of possible outcomes. Since there are 6 equally likely outcomes, each number has a 1/6 chance of being rolled.
Outcomes 2 4 6 8 10 12
Frequency 10 9 6 15 13 8
Expected Probability 1/6 1/6 1/6 1/6 1/6 1/6
To find the largest discrepancy between the experimental and expected probability, we need to calculate the absolute difference between the experimental and expected probabilities for each outcome, and then take the maximum of those differences.
Outcome 2 4 6 8 10 12
Expected Probability 1/6 1/6 1/6 1/6 1/6 1/6
Experimental Probability 10/61 9/61 6/61 15/61 13/61 8/61
Absolute Difference |1/6 - 10/61| |1/6 - 9/61| |1/6 - 6/61| |1/6 - 15/61| |1/6 - 13/61| |1/6 - 8/61|
Absolute Difference 0.044 0.027 0.017 0.068 0.049 0.028
The largest absolute difference is 0.068, which occurs for the outcome of 8. Therefore, the largest discrepancy between the experimental and expected probability is 0.068, or 7% when rounded to the nearest whole number.
It says its wrong
I apologize for the mistake in my previous response. After reviewing my work, I realized that I made an error in the calculation of the expected probability.
To calculate the expected probability, we divide the frequency of each outcome by the total number of rolls:
Outcome 2 4 6 8 10 12
Frequency 10 9 6 15 13 8
Total Rolls 61
Expected Probability 10/61 9/61 6/61 15/61 13/61 8/61
Now we can calculate the absolute difference between the experimental probability (frequency divided by total rolls) and the expected probability for each outcome:
Outcome 2 4 6 8 10 12
Expected Probability 10/61 9/61 6/61 15/61 13/61 8/61
Experimental Probability 10/61 9/61 6/61 15/61 13/61 8/61
Absolute Difference 0 0 0 0 0 0
Since the absolute difference is 0 for all outcomes, there is no discrepancy between the experimental and expected probabilities for this experiment.
Again, I apologize for any confusion in my previous response, and I hope this clarification helps.
Use the table to answer the question.
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Outcomes 2 4 6 8 10 12
Frequency 10 9 6 15 13 8
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Jede tossed a cube with faces numbered with 2, 4, 6, 8, 10, and 12. The results are recorded in the table. What is the largest discrepancy between the experimental and the expected probability of this experiment? The answer needs to be in percent form to the nearest whole number.
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