I need help solving this equation please.
Use the qudratic formula to find any x-intercepton the graph of the equation.
Y=3x^2+9-1
To solve the equation and find the x-intercepts, we will first rewrite the equation in the form "ax^2 + bx + c = 0".
Given equation: y = 3x^2 + 9x - 1
To find the x-intercepts, we set y = 0 and solve for x. Therefore, we have:
0 = 3x^2 + 9x - 1
Now, we compare this equation to the standard quadratic equation form, where ax^2 + bx + c = 0:
a = 3
b = 9
c = -1
Next, we can use the quadratic formula to solve for x:
x = (-b ± sqrt(b^2 - 4ac)) / 2a
Let's substitute the values into the quadratic formula:
x = (-(9) ± sqrt((9)^2 - 4(3)(-1))) / (2(3))
Simplifying further:
x = (-9 ± sqrt(81 + 12)) / 6
x = (-9 ± sqrt(93)) / 6
Therefore, the x-intercepts of the graph of the equation y = 3x^2 + 9x - 1 are:
x = (-9 + sqrt(93)) / 6
x = (-9 - sqrt(93)) / 6