If n=5 and r=1 (1+b)=10a,determine b in terms of a
what do n and r have to do with the problem?
N is over the sigma sign which is 5 and r is under the sigma sign which is =1.......
so you have
5
∑ (1+b) = 10a
1
I still don't get it. Can you edit the expressions above to include everything?
If it's as written,
5(1+b) = 10a
1+b = 2a
a = (1+b)/2
Steve can you help me on mine
To determine the value of b in terms of a when (1+b) equals 10a, we can use algebraic manipulation.
Given:
n = 5
r = 1
(1 + b) = 10a
First, let's substitute the given values of n and r into the equation:
(1 + b) = 10a
(1 + b) = 10 * 5^1
Simplifying, we have:
(1 + b) = 10 * 5
(1 + b) = 50
Now, we can isolate b by subtracting 1 from both sides of the equation:
1 + b - 1 = 50 - 1
b = 49
Therefore, b equals 49 when (1+b) equals 10a.