A car with a velocity of 19 m/s is accelerated uniformly at the rate of 1.8 m/s2 for 6.8 s. What is its final velocity?
Vf=Vi+at
Vf=?
Vi=19 m/s
a=1.8 m/s^2
t=6.8
Vf is what are we are trying to find.
So, Vf=(19 m/s)+(1.8 m/s^2)x(6.8s)
Vf= 31.24 m/s
But because of significant figures, our final answer would be 31 m/s.
To find the final velocity of the car, we can use the formula for uniformly accelerated motion:
v = u + at
Where:
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
Given:
u = 19 m/s (initial velocity)
a = 1.8 m/s^2 (acceleration)
t = 6.8 s (time)
Now let's substitute the given values into the formula:
v = 19 m/s + (1.8 m/s^2)(6.8 s)
To find the solution, we can calculate the right side of the equation:
v = 19 m/s + 12.24 m/s
By adding the two values, we get:
v = 31.24 m/s
Therefore, the final velocity of the car is 31.24 m/s.