A car starting from rest is accelerated uniformly to a velocity of 100.8km/h.A Break is applied in 4 second
Find its acceleration
Find its retardation
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kaduna
To find the acceleration of the car, we need to use the formula:
acceleration (a) = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 0 (starting from rest)
Final velocity (v) = 100.8 km/h
Time (t) = 4 seconds
First, we need to convert the final velocity from km/h to m/s:
1 km/h = 0.2778 m/s
So, the final velocity in m/s is:
100.8 km/h * 0.2778 m/s = 28 m/s
Using the formula, we can calculate the acceleration:
a = (v - u) / t
a = (28 m/s - 0 m/s) / 4 s
a = 7 m/s²
Therefore, the acceleration of the car is 7 m/s².
To find the retardation, we can use the same formula, but with the negative sign since the brake is applied, causing a decrease in velocity.
Retardation (or deceleration) = (final velocity - initial velocity) / time
Given:
Initial velocity (u) = 100.8 km/h
Final velocity (v) = 0 (coming to rest)
Time (t) = 4 seconds
Converting the initial velocity from km/h to m/s:
100.8 km/h * 0.2778 m/s = 28 m/s
Using the formula, we can calculate the retardation:
R = (v - u) / t
R = (0 m/s - 28 m/s) / 4 s
R = -7 m/s² (negative sign indicates retardation/deceleration)
Therefore, the retardation of the car is -7 m/s².
To find the acceleration of the car, we can use the formula:
acceleration = (final velocity - initial velocity) / time
Given that the car starts from rest (initial velocity = 0), the final velocity is 100.8 km/h, and the time is 4 seconds, we can convert the final velocity from km/h to m/s:
100.8 km/h = 100.8 * (1000 m / 3600 s) = 28 m/s
Now we can calculate the acceleration:
acceleration = (28 m/s - 0 m/s) / 4 s = 7 m/s^2
Therefore, the acceleration of the car is 7 m/s^2.
To find the retardation (negative acceleration) when the brakes are applied, we can use the same formula:
retardation = (final velocity - initial velocity) / time
Here, the initial velocity is 100.8 km/h (converted to 28 m/s) and the final velocity is 0 m/s (when the car comes to a stop). The time is given as 4 seconds.
retardation = (0 m/s - 28 m/s) / 4 s = -7 m/s^2
Therefore, the retardation of the car when the brakes are applied is -7 m/s^2.