find the quotient: (-49y^4+42y^3)/7y
factor the numerator.
7y^3(-7y+6)/7y
does that help?
-49y^4 / 7y + 42y^3 / 7y =
-7y^3 + 6y^2 = Quotient.
The quotient can be factored if required:
y^2(-7y + 6).
To find the quotient (-49y^4 + 42y^3) / 7y, we can divide each term in the numerator by the denominator separately.
Let's start by dividing -49y^4 by 7y:
-49y^4 / 7y = -((7 * 7 * 7 * y * y * y * y) / (7 * y)) = -7y^3.
Next, let's divide 42y^3 by 7y:
42y^3 / 7y = (7 * 6 * y * y * y) / (7 * y) = 6y^2.
Therefore, the quotient (-49y^4 + 42y^3) / 7y is -7y^3 + 6y^2.