When a 4.0-ohm resistor is linked to a circuit with a 12-volt battery, what change will occur in the current if the 12-volt battery is substituted with a 6.0-volt battery?
To determine the change in current, we can use Ohm's Law which states that the current (I) in a circuit is equal to the voltage (V) divided by the resistance (R).
For the 12-volt battery:
I = V / R
I = 12V / 4.0Ω
I = 3.0 A
Therefore, the current in the circuit with the 12-volt battery is 3.0 amperes.
For the 6.0-volt battery:
I' = V' / R
I' = 6.0V / 4.0Ω
I' = 1.5 A
Therefore, the current in the circuit with the 6.0-volt battery is 1.5 amperes.
The change in current when the 12-volt battery is substituted with a 6.0-volt battery is a decrease from 3.0 amperes to 1.5 amperes.