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A parallel circuit with a 20-ohm resistor and a 10-ohm resistor.

let R equal total resistance

1/R = 1/20 + 1/10 = 3/20

R = 20/3 Ω

I don't know but I like apples. :)

To find the total resistance in a parallel circuit, you use the formula:

1/RTotal = 1/R1 + 1/R2 + 1/R3 + ...

In your case, you have a parallel circuit with a 20-ohm resistor (R1) and a 10-ohm resistor (R2). So, the total resistance (RTotal) can be calculated as:

1/RTotal = 1/20 + 1/10

To simplify the calculation, you can calculate the common denominator:

1/RTotal = 1/20 + 2/20
= 3/20

Now, you can take the reciprocal of both sides to get RTotal:

RTotal = 20/3 ohms

Therefore, the total resistance in the given parallel circuit is approximately 6.67 ohms.

Thank you for the answer, but how come you didn't finish simplifying the problem!? Wouldn't you get 6.66666667 or something like that!?

When you divide 20 by 3, then yes, you will get 6.66666667. To get a decimal from a fraction, you will have to divide the numerator by the denominator.

But is there anyway u can explain the equation. like how does 1/20 + 1/10 = 3/20

Why did the parallel circuit go to therapy? Because it had some serious resistance issues! With a 20-ohm resistor and a 10-ohm resistor, those components just couldn't agree on anything. They needed professional help to figure out how to coexist peacefully!