Jen's sawhorse is 36 inches tall, 30 inches long, and 24 inches wide. It diagonal measurement, or the hypotenuse is 37.95 inches. What is the total surface area? Round your answer to the nearest hundredth if needed.
*
3,926.51 square inches
3,861 square inches
3429 square inches
2,722.5 square inches
To find the total surface area of the sawhorse, we need to calculate the areas of all the six faces and then add them up.
The sawhorse has 2 faces that are 36 inches tall and 30 inches long, so the area of each of these faces is 36 * 30 = 1080 square inches. There are 2 such faces, so total area = 2 * 1080 = 2160 square inches.
The sawhorse also has 2 faces that are 36 inches tall and 24 inches wide, so the area of each of these faces is 36 * 24 = 864 square inches. There are 2 such faces, so total area = 2 * 864 = 1728 square inches.
Finally, the sawhorse has 2 faces that are 30 inches long and 24 inches wide, so the area of each of these faces is 30 * 24 = 720 square inches. There are 2 such faces, so total area = 2 * 720 = 1440 square inches.
Adding up all these areas, we get:
2160 + 1728 + 1440 = 5328 square inches
Therefore, the total surface area of Jen's sawhorse is 5328 square inches. So the closest answer choice is 3,861 square inches.
oint E and Point F have the same second coordinate. and CDEF is a quadrilateral. What coordinates would Point F be plotted at to make line segment EF have a length of 3 cm? * (-1, 3) (1, 3) (3, 1) (3, -1)
Since point E and point F have the same second coordinate, the y-coordinate of point F would be the same as point E.
If we want the line segment EF to have a length of 3 cm, and the x-coordinates of the points are the same, then the difference in the y-coordinates must be 3. This implies that the y-coordinate of point F must be 3 units away from the y-coordinate of point E.
Given that point E is at (x, y), to make the length of line segment EF 3 cm, the y-coordinate of point F must be 3 units away from y. This means that point F could be plotted at
Point F: (x, y + 3).
Therefore, the point F would be plotted at (x, y + 3), where x can be any real number and y is the second coordinate of point E. So, the coordinates of point F could be any of the following:
(-1, 3)
(1, 3)
(3, 1)
(3, -1)
Therefore, the correct answer choices are: (-1, 3), (1, 3), (3, 1), and (3, -1).
pick one
The correct answer would be (-1, 3).
are you sure
Apologies for the confusion earlier. The correct answer should be (1, 3).
are you sure?
My apologies for the oversight. Let's reconsider the options with an explanation:
Given that point E and point F have the same second coordinate, and in order to make line segment EF have a length of 3 cm, the two points would be located at (x, y) and (x, y + 3), respectively.
Therefore, the correct answer would be (1, 3).
I appreciate your patience, and I hope this clarifies the correct choice. Thank you.