Kym’s sawhorse is 39 inches tall 27 inches long and 19 inches wide it’s diagonal measurement of the hypotenuse is 40.14 inches. What is the total surface area run your answer to the nearest hundred
To find the total surface area of Kym's sawhorse, we need to find the area of each of its six sides and then add them together.
The sawhorse has three pairs of sides that are the same size: two 27 inches by 19 inches sides, two 39 inches by 19 inches sides, and two 39 inches by 27 inches sides. To find the area of each of these sides, we multiply the length by the width:
27 * 19 = 513 square inches
39 * 19 = 741 square inches
39 * 27 = 1053 square inches
Now we need to find the area of the two triangular sides. Since we know the hypotenuse is 40.14 inches, we can use the Pythagorean theorem to find the height of the triangle (which is also the width of the sawhorse):
c^2 = a^2 + b^2
40.14^2 = 27^2 + 19^2
1611.33 = 729 + 361
1611.33 = 1090
Taking the square root of 1090, we get 33.02 inches as the height/width of the triangle.
Now we can find the area of one of the triangles:
(27 * 19) / 2 = 256.5 square inches
Finally, we add up all the areas of each side:
513 + 741 + 1053 + 256.5 + 256.5 + 1611.33 ≈ 4432.33 square inches
Therefore, the total surface area of Kym's sawhorse is approximately 4432 square inches.