Evaluate the distance between the point p(5,-3,4) and the x axis
The distance between a point P(x,y,z) and the x-axis can be found by simply taking the absolute value of the y-coordinate of point P.
In this case, the point P(5,-3,4) has a y-coordinate of -3. Thus, the distance between the point P and the x-axis is | -3 | = 3 units.
Therefore, the distance between the point P(5,-3,4) and the x-axis is 3 units.