Use the table to answer the question.
Outcomes K I N D
Frequency 120 140 105 135
A spinner is divided into 4 sections labeled as K , I , N , D . Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant on the next spin?
(1 point)
Responses
0.24
0.24
0.45
0.45
0.72
0.72
0.28
0.28
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To find the approximate probability of the spinner stopping on a consonant, we need to add up the frequencies of the outcomes K, N, and D which represent the consonants.
Total frequency of consonants = 140 + 105 + 135 = 380
Total frequency of all outcomes = 120 + 140 + 105 + 135 = 500
Probability of stopping on a consonant = Frequency of consonants / Total frequency of all outcomes
Probability = 380 / 500 ≈ 0.76
Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.76.
None of the given answer choices match this calculation.
wrong
I apologize for the error. Let's recalculate the probability of the spinner stopping on a consonant.
Frequency of consonants (K, N, D) = 140 + 105 + 135 = 380
Total frequency of all outcomes = 500
Probability of stopping on a consonant = Frequency of consonants / Total frequency of all outcomes
Probability = 380 / 500 = 0.76
Therefore, the approximate probability that the spinner will stop on a consonant on the next spin is 0.76, which is equivalent to 76% or 0.76. Thank you for your patience.