Outcomes K I N D
Frequency 120 140 105 135
A spinner is divided into 4 sections labeled as K, I, N, D. Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant of the next spin?
a. 0.72
b. 0.24
c. 0.28
d. 0.45
First, we need to determine the total number of spins for consonants, which are K, N, and D.
Total frequency of consonants = 120 + 105 + 135 = 360
Therefore, the probability of landing on a consonant in the next spin is:
P(consonant) = Total frequency of consonants / Total number of spins
P(consonant) = 360 / 500
P(consonant) = 0.72
Therefore, the approximate probability that the spinner will stop on a consonant of the next spin is 0.72, so the answer is:
a. 0.72
Use the tables to answer the question.
Simon's Results
Number of white balls selected Number of red balls selected
Bowl A 15 16
Bowl B 16 4
Clark's Results Number of white balls selected Number of red balls selected
Bowl A 45 55
Bowl B 60 40
Bowls A and B contain certain number of white and red balls. Simon and Clark repeatedly selected a ball from both bowls and recorded the results in a table. Whose results will give you a better indication about the proportion of white and red balls in each in each bowl? Explain your answer.
a. neither
b. both results can be used
c. clark's experiment
d. Simon's experiment
To determine which results give a better indication of the proportion of white and red balls in each bowl, we need to consider both the total number of white and red balls selected by each person and the consistency of their results.
Clark's results are more reliable as he has a larger sample size for each bowl. Clark's results show 100 selections for each bowl, which can provide a more accurate indication of the proportion of white and red balls in each bowl.
Simon's results, on the other hand, have a much smaller sample size with only 31 selections in total, 31 selections might not provide a reliable indication of the proportion of white and red balls in each bowl.
Therefore, it can be concluded that Clark's results provide a better indication of the proportion of white and red balls in each bowl. So, the correct answer is:
c. Clark's experiment
Number of white balls selected Number of red balls selected
Bowl A 15 16
Bowl B 16 4
Bowls A and B contain certain number of white and red balls. Simon repeatedly selected a ball from both bowls and recorded the results in a table. Using Simon's results, what is the experimental probability of picking a red ball from Bowl A? The answer needs to be in percent form.
a. 78.95%
b. 37.5%
c. 75%
d. 25%
To calculate the experimental probability of picking a red ball from Bowl A using Simon's results, we need to use the formula for experimental probability:
Experimental Probability = Number of favorable outcomes / Number of total outcomes
For Bowl A, the number of red balls selected by Simon is 16 and the total number of selections made from Bowl A is 15 + 16 = 31.
So, the experimental probability of picking a red ball from Bowl A according to Simon's results is:
Experimental Probability = 16 / 31 ≈ 0.5161
Converting this to a percentage:
Experimental Probability ≈ 0.5161 * 100 ≈ 51.61%
Therefore, the experimental probability of picking a red ball from Bowl A according to Simon's results is approximately 51.61%. Therefore, the closest answer choice is:
a. 78.95%