A big flower vase has 5 begonias, 6 carnations, and 7 tulips. Two flowers are randomly selected without replacement. What is the probability of selecting two carnations? Express the answer in the simplest form of fraction.(1 point)

Question

A big flower vase has 5 begonias, 6 carnations, and 7 tulips. Two flowers are randomly selected without replacement. What is the probability of selecting two carnations? Express the answer in the simplest form of fraction.(1 point)

Answer 1

The total number of flowers in the vase is 5 + 6 + 7 = 18.

The probability of selecting a carnation on the first pick is 6/18 = 1/3.

After selecting a carnation on the first pick, there are now only 17 flowers in the vase, with 5 begonias, 5 carnations, and 7 tulips left.

The probability of selecting a carnation on the second pick is 5/17.

Therefore, the overall probability of selecting two carnations is:

(1/3) * (5/17) = 5/51

So, the probability of selecting two carnations is 5/51.

Answer 2

A standard deck of 52 cards contains four suits: hearts, diamonds, clubs, and spades. Each suit has 13 cards: ace, 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, and king. Two cards are randomly drawn without replacement. Calculate the probability of drawing two diamond cards. Express your answer in percent form rounding to the nearest hundredth.(1 point)