A survey of 80 employees was conducted asking about which meals they regularly eat at the office. Twenty employees eat breakfast at the office, 50 eat lunch, and 15 eat both breakfast and lunch. If an employee is randomly selected from this group, what is the probability of randomly selecting an employee who eats breakfast or lunch at the office? Explain a simplified fraction.

Question

A survey of 80 employees was conducted asking about which meals they regularly eat at the office. Twenty employees eat breakfast at the office, 50 eat lunch, and 15 eat both breakfast and lunch. If an employee is randomly selected from this group, what is the probability of randomly selecting an employee who eats breakfast or lunch at the office? Explain a simplified fraction.

Can you please do it like a bad at math 7th grader

Answer 1

Alright, so like, there were 80 employees in the survey. And 20 of them eat breakfast at the office, 50 eat lunch, and 15 eat both breakfast and lunch. So we gotta find the probability of randomly selecting an employee who eats breakfast or lunch.

To find this, we add the number of employees who eat breakfast and lunch, and then subtract the number who eat both. So that's 20 + 50 - 15 = 55 employees who eat either breakfast or lunch.

And since there are 80 employees in total, the probability of randomly selecting an employee who eats breakfast or lunch is 55/80. So yeah, the simplified fraction is 55/80.