A survey of 80 employees was conducted asking about which meals they regularly eat at the office. Twenty employees eat breakfast at the office, 50 eat lunch, and 15 eat both breakfast and lunch. If an employee is randomly selected from this group, what is the probability of randomly selecting an employee who eats breakfast or lunch at the office?
To find the probability of randomly selecting an employee who eats breakfast or lunch at the office, we need to find the total number of employees who eat breakfast or lunch.
There are 20 employees who eat breakfast, 50 employees who eat lunch, and 15 employees who eat both breakfast and lunch. To avoid double counting, we need to subtract the employees who eat both breakfast and lunch from the total number of employees who eat breakfast or lunch.
Total employees who eat breakfast or lunch = Employees who eat breakfast + Employees who eat lunch - Employees who eat both
= 20 + 50 - 15
= 55 employees
Therefore, the probability of randomly selecting an employee who eats breakfast or lunch at the office is 55/80 or 0.6875, which can also be expressed as 68.75%.