A survey of 80 employees was conducted, asking about which meals they regularly eat at the office. 20 employees eat breakfast at the office, 50 eat lunch, and 10 eat breakfast and lunch. If an employee is randomly selected from this group, what is the probability of randomly selecting an employee who eats breakfast or lunch at the office?
To find the probability of randomly selecting an employee who eats breakfast or lunch at the office, we need to find the total number of employees who eat breakfast or lunch, and then divide that by the total number of employees surveyed.
From the information given:
- 20 employees eat breakfast
- 50 employees eat lunch
- 10 employees eat both breakfast and lunch
Adding these numbers together gives us:
20 (breakfast) + 50 (lunch) - 10 (both) = 60 employees eat either breakfast or lunch at the office.
Therefore, the probability of randomly selecting an employee who eats breakfast or lunch at the office is:
60 (employees who eat breakfast or lunch) / 80 (total employees surveyed) = 0.75
So the probability is 0.75 or 75%.