A survey of 80 employees was conducted asking about which meals they regularly eat at the office 20 employees eat breakfast at the office 50 eat lunch and 10 eat both breakfast and lunch if an employees randomly selected from this group what is the probability of randomly selecting an employee who eats breakfast or lunch at the office? Is the answer 5/8?

Question

A survey of 80 employees was conducted asking about which meals they regularly eat at the office 20 employees eat breakfast at the office 50 eat lunch and 10 eat both breakfast and lunch if an employees randomly selected from this group what is the probability of randomly selecting an employee who eats breakfast or lunch at the office? Is the answer 5/8?

Answer 1

Yes, you are correct.

There are a total of 80 employees surveyed.
20 employees eat breakfast + 50 employees eat lunch - 10 employees eat both breakfast and lunch = 60 employees eat breakfast or lunch at the office.

So the probability of randomly selecting an employee who eats breakfast or lunch at the office is 60/80 = 3/4 = 0.75 = 75%.

Therefore, the answer is not 5/8 but indeed 3/4.