1. A group of 29 campers is going on a field trip. Each car that goes on the trip can
take 4 campers. Write an inequality that shows the minimum number of cars that
will be sufficient to transport all the campers.
2. The camp parking lot has room for 10 cars. The camp counselors have already
parked their 2 cars in the lot. Write an inequality to show the additional number
of cars that can park in the lot.
3. Solve both inequalities. What number is a solution of both inequalities? If 29
campers need to be transported, and the cars need to gather in the camp parking
lot before driving out, how many cars should be used for the trip?
1. Let x be the minimum number of cars needed to transport all 29 campers. The inequality would be:
4x ≥ 29
2. Let y be the additional number of cars that can park in the lot. Since the camp counselors have already parked their 2 cars, the inequality would be:
y ≤ 10 - 2 = 8
3. Solving the first inequality:
4x ≥ 29
x ≥ 29 / 4
x ≥ 7.25
Since x must be a whole number as we can't have a fraction of a car, x must be at least 8 cars.
Solving the second inequality:
y ≤ 8
Therefore, the number that is a solution of both inequalities is 8 cars. So, 8 cars should be used to transport the 29 campers on the field trip.