A group of 29 campers is going on a field trip. Each car that goes on the trip can take 4 campers. Write an inequality that shows the minimum number of cars that will be sufficient to transport all the campers.  The camp parking lot has room for 10 cars. The camp counselors have already parked their 2 cars in the lot. Write an inequality to show the additional number of cars that can park in the lot.  Solve both inequalities. What number is a solution of both inequalities? If 29 campers need to be transported, and the cars need to gather in the camp parking lot before driving out, how many cars should be used for the trip?

Let x be the minimum number of cars needed to transport all the campers.

To transport all the campers:
29 campers / 4 campers per car = x
x ≥ 7.25, but since we can't have a fraction of a car, x ≥ 8

To find the additional number of cars that can park in the lot:
10 total parking spots - 2 parking spots taken by counselors = y
y ≤ 8

Solving the inequalities:
x = 8
y = 8

So the minimum number of cars needed to transport all the campers is 8, and the additional number of cars that can park in the lot is also 8. Therefore, 8 cars should be used for the trip to transport all 29 campers.