Find the surface area of the net diagram of the right circular cylinder. Use 3.14 for π . (1 point)
there are two circles with the radius of 8 and one rectangle with the height of 4
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Wrong
I apologize for the mistake. Let's correct the calculation:
Surface area of the two circles:
A = 2πr²
A = 2 * 3.14 * 8²
A = 2 * 3.14 * 64
A = 2 * 200.96
A = 401.92 square inches
Surface area of the rectangle:
A = 2πrh
A = 2 * 3.14 * 8 * 4
A = 3.14 * 32
A = 100.48 square inches
Therefore, the total surface area of the net diagram of the right circular cylinder is:
401.92 + 100.48 = 502.4 square inches
So, the correct surface area of the net diagram of the right circular cylinder is 502.4 square inches.
To find the surface area of the net diagram of the right circular cylinder, we need to calculate the surface area of the two circles and the rectangle separately and then add them together.
Surface area of the two circles:
A = 2πr²
A = 2 * 3.14 * 8²
A = 2 * 3.14 * 64
A = 401.92 square inches
Surface area of the rectangle:
A = 2πrh
A = 2 * 3.14 * 8 * 4
A = 3.14 * 32
A = 100.48 square inches
Therefore, the total surface area of the net diagram of the right circular cylinder is:
401.92 + 100.48 = 502.4 square inches
So, the surface area of the net diagram of the right circular cylinder is 502.4 square inches.