LeBron's average bowling score for the season is 180 with a standard deviation of 28 Use technology to determine which of the following represents the probability that LeBron records a score higher than 200.
To determine the probability that LeBron records a score higher than 200, we need to calculate the z-score for a score of 200 and then find the corresponding probability using a standard normal distribution table.
The z-score formula is:
z = (X - μ) / σ
Where:
X = score of 200
μ = mean score of 180
σ = standard deviation of 28
Plugging in the values:
z = (200 - 180) / 28
z = 20 / 28
z = 0.7143
Next, we will use a standard normal distribution table or a calculator to find the probability associated with a z-score of 0.7143. From the table or calculator, we find that the probability of scoring higher than 200 is approximately 0.2392 or 23.92%.
Therefore, the probability that LeBron records a score higher than 200 is 23.92%.