LeBron’s average bowling score for the season is 180 with a standard deviation of 28. Use technology to determine which of the following represents the probability that LeBron records a score higher than 200
A. 17%
B. 23.8%
C. 1.1%
D. 76.2%
To calculate the probability that LeBron records a score higher than 200, we can use a Z-score calculation.
Z = (X - μ) / σ
Z = (200 - 180) / 28
Z = 0.7143
Using a Z-table or calculator, we can find that the probability of a Z-score of 0.7143 or higher is approximately 23.8%. Therefore, the correct answer is B. 23.8%.
is this right
I apologize for the mistake in my previous response. Let me correct it.
To calculate the probability that LeBron records a score higher than 200, we need to first convert 200 to a Z-score using the formula:
Z = (X - μ) / σ
Z = (200 - 180) / 28
Z = 0.7143
Next, we look up the probability corresponding to a Z-score of 0.7143 in a standard normal distribution table or by using a calculator.
The probability of a Z-score of 0.7143 or higher is approximately 23.8%. Therefore, the correct answer is B. 23.8%.