Refer to the chemical equation Pb(NO3)2 + 2NaI → PbI2 + 2NaNO3.
Identify the products and list the number of each type of atom present in the products.
Describe how the products differ from the reactants and how they are similar.
Explain why or why not matter is conserved in this chemical reaction.
Products: PbI2 and 2NaNO3
Number of atoms in the products:
PbI2 - 1 lead (Pb) atom, 2 iodide (I) atoms
NaNO3 - 2 sodium (Na) atoms, 2 nitrate (NO3) molecules
Differences between products and reactants: The products have different chemical compositions compared to the reactants. Lead iodide (PbI2) and sodium nitrate (NaNO3) are formed from the reaction of lead nitrate (Pb(NO3)2) and sodium iodide (NaI). The products have different physical and chemical properties compared to the reactants.
Similarities between products and reactants: Both the reactants and products contain the same elements (lead, iodine, sodium, nitrogen, and oxygen), but in different combinations.
Conservation of matter: Matter is conserved in this chemical reaction because the total number of each type of atom (lead, iodine, sodium, nitrogen, and oxygen) remains the same before and after the reaction. The number of atoms of each element is equal on both sides of the chemical equation. Therefore, matter is conserved in this reaction.