Question 36 Find the vertex of the following quadratic equation. Answer as an ordered pair (x,y)
y = 2x^2 + 8
To find the vertex of the quadratic equation y = 2x^2 + 8, we can use the formula x = -b/2a to find the x-coordinate of the vertex.
In this case, a = 2 and b = 0, because there is no linear term in the equation.
Therefore, x = -0 / (2 * 2) = 0.
Now, substitute x = 0 back into the equation to find the y-coordinate:
y = 2(0)^2 + 8
y = 0 + 8
y = 8
Therefore, the vertex of the quadratic equation y = 2x^2 + 8 is (0, 8).