Question 36 Find the vertex of the following quadratic equation. Answer as an ordered pair (x,y)
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y+2x^2+8
The vertex of a quadratic equation in the form y = ax^2 + bx + c is given by the coordinates (-b/2a, f(-b/2a)).
For the equation given, y = 2x^2 + 8, the coefficient of x^2 is 2 and the coefficient of x is 0.
Therefore, a = 2 and b = 0.
The x-coordinate of the vertex is:
x = -b/(2a) = -0 / (2*2) = 0
To find the y-coordinate, substitute x = 0 into the equation:
y = 2(0)^2 + 8 = 0 + 8 = 8
Therefore, the vertex of the quadratic equation y = 2x^2 + 8 is (0, 8).