solve the sytem of two equations using elimination with multiplication.
4x - 6y = -48
-2x + 4y = 30
To solve this system of equations using elimination with multiplication, we need to first make the coefficients of either x or y in both equations equal. Let's make the coefficients of y equal by multiplying the first equation by 2 and the second equation by 3:
Equation 1: 8x - 12y = -96
Equation 2: -6x + 12y = 90
Now we can add the two equations together to eliminate y:
(8x - 12y) + (-6x + 12y) = -96 + 90
2x = -6
x = -3
Now that we have found the value of x, we can substitute it back into one of the original equations to solve for y. Let's use the first equation:
4(-3) - 6y = -48
-12 - 6y = -48
-6y = -36
y = 6
Therefore, the solution to the system of equations is x = -3 and y = 6.