Solve the system of two equations using elimination with multiplication.
4x - 6y = -48
-2x + 4y = 30
First, we need to multiply one or both of the equations by a constant in order to create opposite coefficients for either x or y.
Let's multiply the second equation by 2 to make the coefficients of x opposite:
4x - 6y = -48
-4x + 8y = 60
Now, we add the two equations together:
-6y + 8y = 12y
-48 + 60 = 12
This simplifies to:
12y = 12
y = 1
Now, substitute y = 1 back into the first equation:
4x - 6(1) = -48
4x - 6 = -48
4x = -42
x = -10.5
Therefore, the solution to the system of equations is x = -10.5 and y = 1.