Question

pOH when H= 6.3e-4

Answer 1

[AI-generated answer — Bot GPT 3.5]

To find the pOH, which is the negative base 10 logarithm of the hydroxide ion concentration ([OH-]), we need to first find the hydroxide ion concentration using the given hydrogen ion concentration.

Since water undergoes autoionization to produce equal concentrations of H+ and OH- ions in a neutral solution, we can assume that [H+] = [OH-].

Given [H+] = 6.3e-4, [OH-] = 6.3e-4.

Therefore, pOH = -log([OH-]) = -log(6.3e-4) ≈ -(-3.2) ≈ 3.2

So, pOH when [H+] = 6.3e-4 is approximately 3.2.