What is the (a) [H+], (b) [OH-], (c) pH, and (d) pOH of a 0.002 M solution of HNO3?

To determine the values of (a) [H+], (b) [OH-], (c) pH, and (d) pOH of a 0.002 M solution of HNO3, we can use some basic concepts in chemistry.

(a) [H+]:
HNO3 is a strong acid, meaning it fully dissociates in water to produce H+ ions and NO3- ions. Since the concentration of HNO3 is 0.002 M, the concentration of H+ ions is also 0.002 M.

(b) [OH-]:
In water, H+ ions and OH- ions are present as a result of the self-ionization of water. However, in this case, because HNO3 is a strong acid, it completely reacts with water, leaving no OH- ions in the solution. Therefore, the concentration of OH- ions is zero.

(c) pH:
The pH of a solution can be calculated using the equation pH = -log[H+]. Substituting the concentration of H+ ions (0.002 M) into the equation gives:

pH = -log(0.002)
pH ≈ 2.70

(d) pOH:
The pOH of a solution can be calculated using the equation pOH = -log[OH-]. Since the concentration of OH- ions is zero, the pOH of this solution is undefined.

Therefore, the answers are:
(a) [H+]: 0.002 M
(b) [OH-]: 0 M
(c) pH: 2.70
(d) pOH: undefined

To find the (a) [H+], (b) [OH-], (c) pH, and (d) pOH of a 0.002 M solution of HNO3, we need to understand the properties of the acid and its dissociation in water.

HNO3 is a strong acid, which means it will dissociate completely in water, producing H+ ions and the conjugate base NO3-.

(a) [H+]:
Since HNO3 is a strong acid and will dissociate completely, the concentration of [H+] in the solution will be equal to the initial concentration of the acid. Therefore, [H+] = 0.002 M.

(b) [OH-]:
To find the concentration of the hydroxide ions, [OH-], we need to consider water autoprotolysis. Water molecules can act as both acids and bases, forming H+ and OH-. In pure water, the concentration of [H+] and [OH-] is 10^-7 M. However, in an acidic solution like HNO3, the concentration of [OH-] will be very small since it is consumed by the reaction with H+.

(c) pH:
The pH is a logarithmic scale that measures the acidity or basicity of a solution. It is calculated using the formula: pH = -log[H+].
In this case, the concentration of [H+] is 0.002 M, so we can calculate the pH using the equation: pH = -log(0.002).
Using a logarithm calculator or math software, we find that the pH is approximately 2.70.

(d) pOH:
The pOH is another logarithmic scale that represents the concentration of OH- ions in a solution. It is calculated using the formula: pOH = -log[OH-].
Since we know that [OH-] is small and insignificant in an acidic solution like HNO3, we can assume that the pOH is close to 7 (the pOH of pure water).

See your first problem. After I've done one of these you should be able to follow the same reasoning to work the same kind of other problems.