Inequalities: Apply
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A group of 29 campers is going on a field trip. Each car that goes on the trip can take 4 campers. Write an inequality that shows the minimum number of cars that will be sufficient to transport all the campers.
The camp parking lot has room for 10 cars. The camp counselors have already parked their 2 cars in the lot. Write an inequality to show the additional number of cars that can park in the lot.
Solve both inequalities. What number is a solution of both inequalities? If 29 campers need to be transported, and the cars need to gather in the camp parking lot before driving out, how many cars should be used for the trip?
1. Let x represent the number of cars needed for the field trip. The inequality would be: 29 <= 4x
2. Let y represent the number of additional cars that can park in the lot. The inequality would be: y + 2 <= 10
3. Solving the first inequality:
29 <= 4x
Divide both sides by 4:
7.25 <= x
Since x represents the number of cars needed for the field trip, x must be a whole number. Therefore, x must be at least 8 (rounding up from 7.25).
Now solving the second inequality:
y + 2 <= 10
Subtracting 2 from both sides:
y <= 8
The number that is a solution for both inequalities is 8. Therefore, 8 cars should be used for the trip in order to transport all 29 campers and park in the camp parking lot.