Factor by grouping.
3n3 – 12n2 + 2n – 8
A:(3n2 – 2)(n + 4)
B:(3 n 2 + 2)( n – 4)
C:( n + 2)(3 n – 4)
D:3(n3 –4n2) + 2n – 8
To factor by grouping, let's group the terms together:
(3n^3 - 12n^2) + (2n - 8)
Factor out the common factor from the first group: 3n^2
3n^2(n - 4) + 2n - 8
Now both groups have a common factor: n - 4
(3n^2 + 2)(n - 4)
Therefore, the correct factorization by grouping is:
B: (3n^2 + 2)(n - 4)