Factor the following polynomials by grouping if possible:
acx^2 + adx + bcx + bd
a(c x^2 + d x) +b (c x + d) oh,look, get that x out of the first term
a x( c x + d) + b(c x + d)
so
(a x + b)(c x + d)
thank you so much
You are welcome.
To factor the polynomial acx^2 + adx + bcx + bd by grouping, we will look for common factors between the terms.
Step 1: Group the terms
Group the terms based on common factors:
(acx^2 + adx) + (bcx + bd)
Step 2: Factor out the common factor from each grouping
From the first grouping, factor out the common factor of "acx":
acx(x+d)
From the second grouping, factor out the common factor of "bc":
bc(x+d)
Step 3: Look for a common binomial factor
Now, notice that we have a common binomial factor of (x+d) in both groupings:
(acx + ad) + (bcx + bd)
(x+d)(ac + bc)
Thus, the factored form of the polynomial acx^2 + adx + bcx + bd by grouping is (x+d)(ac + bc).